If f (SiNx) = 2-2cosx, then f (cosx) is equal to A、2-sin2x B、2+sin2x C、2-2cosx D、2+2cosx

From the title,
f(sinx)=2-2cosx,
therefore
f(cosx)
=f(sin(π/2-x))
=2-2cos(π/2-x)
=2-2sinx

RELATED INFORMATIONS

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