Finding f (cosx) by knowing f (SiNx) = sin3x RT
Let SiNx = u, then (cosx) ^ 2 = (1-u ^ 2), f (U) = sin3x = sin (2x + x) = sin2xcosx + cos2xsinx = 2sinx (cosx) ^ 2 + (1-2 (SiNx) ^ 2) SiNx = 2U (1-u ^ 2) + (1-2u ^ 2) u = 3u-4u ^ 3, then f (cosx) = 3cosx-4 (cosx) ^ 3
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