If f (x) is an increasing function defined on (0, positive infinity), and f (XY) = f (x) + F (y) If f (x) is an increasing function defined on (0, positive infinity), and f (XY) = f (x) + F (y) If f (radical 3) = 1, the inequality f (2x + 1) + F (x) < 2 is solved Ask detailed process! Thank you! Very urgent!

If f (x) is an increasing function defined on (0, positive infinity), and f (XY) = f (x) + F (y) If f (x) is an increasing function defined on (0, positive infinity), and f (XY) = f (x) + F (y) If f (radical 3) = 1, the inequality f (2x + 1) + F (x) < 2 is solved Ask detailed process! Thank you! Very urgent!

A:
F (x) is an increasing function defined on x > 0, f (XY) = f (x) + F (y)
f(√3)=1
f(2x+1)+f(x)