p: For any real number x, KX square plus 2, KX minus (k plus 2) is less than 0. Q: for the equation x of X, the square plus x minus K is equal to 0, and there is a real root if P and Q p: For any real number x, KX square plus 2, KX minus (k plus 2) is less than 0. Q: for the equation x of X, the square plus x minus K is equal to 0. There is a real root. If there is only one true proposition between P and Q, the value range of the real number k is determined

p: For any real number x, KX square plus 2, KX minus (k plus 2) is less than 0. Q: for the equation x of X, the square plus x minus K is equal to 0, and there is a real root if P and Q p: For any real number x, KX square plus 2, KX minus (k plus 2) is less than 0. Q: for the equation x of X, the square plus x minus K is equal to 0. There is a real root. If there is only one true proposition between P and Q, the value range of the real number k is determined

∵ KX square plus 2 KX minus (k plus 2) is less than 0, that is kx2-2kx + k-2k-2 < 0 K (x-1) 2 < 2K + 2 (x-1) 2 < 2K + 2 / K
Obviously, inequalities are conditional,
It is a false proposition that "P: for any real number x, KX square plus 2, KX minus (k plus 2) is less than 0"