If any two real numbers a and B are taken in the interval [- 2,2], then the probability of two real numbers of X equation x ^ 2 + ax-b ^ 2 + 1 = 0? The equation is: x ^ 2 + 2ax-b ^ 2 + 1 = 0

If any two real numbers a and B are taken in the interval [- 2,2], then the probability of two real numbers of X equation x ^ 2 + ax-b ^ 2 + 1 = 0? The equation is: x ^ 2 + 2ax-b ^ 2 + 1 = 0

π/2
Delta = a ^ 2 + 4B ^ 2-4 > 0, it is an ellipse, the major and minor axes are 2 and 1 respectively, the area is 2 π, and it is completely in the square of [- 2,2] ^ 2, the area is 4,
SO 2 π / 4 = π / 2