The solution of the system ax + by = 2C CZ + AX = 2B by + CZ = 2A is a. B and C are constant and not 0

ax+by=2c.(1)
cz+ax=2b.(2)
by+cz=2a.(3)
(1)+(2)+(3):
2ax+2by+2cz=2a+2b+2c
∴ax+by+cz=a+b+c.(4)
∵ a, B, C are not 0
(4)-(1):
cz=a+b-c
Divide both sides by C:
z=(a+b-c)/c
(4)-(2):
by=a-b+c
Divide both sides by B:
y=(a-b+c)/b
(4)-(3):
ax=b+c-a
Divide both sides by a:
x=(b+c-a)/a

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