If the solution of the system of equations ax-by-2z = 13, ax + 2Y + CZ = - 2, cx-4y + BZ = 28 is x = 3, y = - 1, z = - 2, find the value of a, B, C
3a+b+4=13 3a+b=9…… (1)3a-2-2c= -2,3a-2c=0…… (2)3c+4-2b=28 3c-2b=24…… (3) (1) - (2) get B + 2C = 9 (4) (4) × 2 gives 2B + 4C = 18 (5) (3) + (5) 7C = 42 C = 6 C = 6 substituting (2) 3A = 12 A = 4C = 6 substituting (4) B = 9
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