Given the two roots of the quadratic equation AX square plus B x plus C equal to zero, this paper proves that ax square plus B x plus C equals a (x minus x1) (x minus x2)

Ax ^ 2 + BX + C = 0
x1+x2=-b/a,x1*x2=c/a,
a(x-x1)(x-x2)
=a[x^2-(x1+x2)x+x1x2]
=a(x^2+b/a*x+c/a)
=ax^2+bx+c,
The proposition is proved

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