Let a, B, C and d be real numbers, and find the values of 2007a + 5B + 8C / 2007x + 5Y + 8Z Let a, B, C, d be real numbers. If the square of a + the square of B + the square of C = 25, the square of X + the square of Y + the square of Z = 36, ax + by + CZ = 30, find 2007a + 5B + 8C / 2007x + 5Y + 8Z, what is the value?

Let a, B, C and d be real numbers, and find the values of 2007a + 5B + 8C / 2007x + 5Y + 8Z Let a, B, C, d be real numbers. If the square of a + the square of B + the square of C = 25, the square of X + the square of Y + the square of Z = 36, ax + by + CZ = 30, find 2007a + 5B + 8C / 2007x + 5Y + 8Z, what is the value?

When a, B and C are real numbers, there are innumerable solutions to this problem
I think the condition of this problem should be that a, B, C, x, y and Z are integers
In this way, we can get the following conclusions
A^2+B^2+C^2=25.(1)
X^2+Y^2+Z^2=36.(2)
AX+BY+CZ=30.(3)
(1) + (2) - 2 * (3) obtained: 1
(A-X)^2+(B-Y)^2+(C-Z)^2=1.(4)
(1) + (2) + 2 * (3) we get the following results
(A+X)^2+(B+Y)^2+(C+Z)^2=121.(5)
It can be seen from formula (4) that in the case of integer, there must be two terms of 0 and the other term of 1
Then let a = x, B = y, C = Z + 1, or C = Z-1 solve C = 5, z = 6, or C = - 5, z = - 6, other values are 0,
So the value of the formula is 5 / 6