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ax^2+bx+c=0,由韋達定理: x1+x2=-b/a,x1*x2=c/a, a(x-x1)(x-x2) =a[x^2-(x1+x2)x+x1x2] =a(x^2+b/a*x+c/a) =ax^2+bx+c, 命題得證.
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