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x=by+cz ax=y-cz =>(a+1)x=(b+1)y 同理可有 (c+1)z=(b+1)y (a+1)x=(c+1)z 原式=ax/(b+1)y + by/(b+1)y + cz/(b+1)y =(ax+by+cz)/(b+1)y =(z+cz)/(b+1)y =1
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