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(a^2+b^2+c^2)+2m(ax+by+cz)+m^2(x^2+y^2+c^2)=(a+mx)^2+(b+my)^2+(c+mz)^2>=0.即:對任意m,1+2(ax+by+cz)m+9m^2>=0恒成立.所以[2(ax+by+cz)]^2-4*9
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