If f (x) = (x + a) cubic has f (1 + x) = - f (1-x) for any real number, then f (2) + F (- 2)=
Because f (1 + x) = - f (1-x)
Let x = 0
F (1) = - f (1), that is, f (1) = 0
So f (1) = (1 + a) ^ 3 = 0, so a = - 1
There is f (x) = (x-1) ^ 3
f(2)+f(-2)=(2-1)^3+(-2-1)^3=1+(-27)=-26
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