Let f (x) = x power of 4 divided by (x power of 4 + 2), if 0

(1) 1-f (a) = 1-4 ^ A / (4 ^ A + 2) = 2 / (4 ^ A + 2) = 4 / (2.4 ^ A + 4) = 4 ^ (1-A) / (4 ^ (1-A) + 2) = f (1-A), so f (a) + f (1-A) = 1 (2) f (1 / 1001) + F (2 / 1001) + F (3 / 1001) + +The value of F (1000 / 1001) + F (1-1000 / 1001) = 1F (999 / 1

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