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(1)1-f(a)=1-4^a/(4^a +2)=2/(4^a +2)=4/(2·4^a+4)=4^(1-a)/(4^(1-a)+2)=f(1-a)所以f(a)+f(1-a)=1(2)f(1/1001)+f(2/1001)+f(3/1001)+……+f(1000/1001)的值f(1000/1001)+f(1-1000/1001)=1f(999/1…
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