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當元素中不存在1時,最小得元素是2設a屬於A 2a=a+a>a+2 囙此集合中必含有1 如果集合中含有4個和4個以上的元素記為N 可以知道最多含有3個元素 不可能有2個元素 囙此只有1+2+3=1*2*3符合 元素之和等於元素之積的所有集合個數為1
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