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∵A={x|f(x)=x}={a},∴方程x2+ax+b=x的兩等根均為a.∴x2+(a-1)x+b=0的兩根均為a.∴a+a=−(a−1)a•a=b,∴a=13b=19,∵元素(a,b)構成的集合為M,∴M={(13,19)}.
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