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Given the set a = {x | X & # 178; + 2x-8 = 0} B = {x | X & # 178; + kx-k = 0} if a intersects B = B, we can find the value range of real number K
X & # 178; + 2x-8 = 0, x = 2 or - 4
If a intersection B = B, x = 2, X & # 178; + kx-k = 0 = =, k = - 4, B = {x | (X-2) & # 178; = 0}
When x = - 4, X & # 178; + kx-k = 0 = = >, k = 16 / 5, B = {x | (x + 4) (5x-4) = 0}, then a intersects B ≠ B
So: k = - 4
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