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Given the function f (x) = AX2 + BX + C, f (- 3) = f (1) = 0, f (0) = - 3, we can find the solution set of the equation f (x) = 2x
From the known conditions: 9a − 3B + C = 0A + B + C = 0C = − 3; the solution is a = 1, B = 2, C = - 3; from F (x) = 2x, the solution is x2 + 2x-3 = 2x; the solution is x = ± 3, and the solution set is {− 3, 3}
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