Given that a, B and X are positive numbers and LG (BX) · LG (AX) + 1 = 0, the value range of AB is obtained

Given that a, B and X are positive numbers and LG (BX) · LG (AX) + 1 = 0, the value range of AB is obtained

∵ a, B, X are positive numbers, and LG (BX) · LG (AX) + 1 = 0, ∵ (LGA + lgx) (LGB + lgx) + 1 = 0, and (lgx) 2 + (LGA + LGB) lgx + 1 + lgalgb = 0, ∵ this equation has a solution, ∵ = (LGA + LGB) 2-4lgalgb-4 ≥ 0 (LGA) 2 + 2lgalgb + (LGB) 2-4lgalgb-4 ≥ 0 (LGA LGB) 2 ≥ 4 LGA LGB ≥ 2 or LGA LGB ≤ - 2lg (a-b) ≥ 2 or LGA / b ≤ - 2 ∵ ab ≥ 100 Or 0 ＜ ab ≤ 1100. The range of AB is (01100) ∪ [100, + ∞)

Elden Ring Premiere

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