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x²;+2x-8=0 x=2或-4 若A交B=B,x=2時x²;+kx-k=0 ==》k= -4,B={x|(x-2)²;=0} x=-4時x²;+kx-k=0 ==》k= 16/5,B={x|(x+4)(5x-4)=0},此時A交B≠B 故:k= -4
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