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∵1∈A;∴若a+2=1,則a=-1,A={1,0,1},不滿足集合的互异性,∴a≠-1;若(a+1)2=1,則a=0,或-2,a=0時,A={2,1,0};a=-2時,A={0,1,2};若|a|=1,則a=±1,由前面知a≠-1;a=1時,A={3,4,1}.綜上得實數a的值為:-2,0,1.
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