Even functions defined on R satisfy the following conditions: for any X &;, X &; ∈ [0, + ∞], there is f (x1) - f (x2) / x1-x2 ＜ 0 The size order of F (3), f (- 2), f (1) (solving process)

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• 1. The even function f (x) defined on R satisfies that for any x1, X2 belongs to (negative infinity, 0) (x1 ≠ x2), and (x2-x1) (f (x2) - f (x1)) > 0, then when n belongs to N +, f（n+1）
• 2. The zero point of the function f (x) = x2-3x + 2 is () A. （1，0），（2，0）B. （0，1），（0，2）C. 1，2D. -1，-2
• 3. Finding the zeros of the function y = (3x-x ^ 2) / (x ^ 2-1) + 1 / (1-x) - 2
• 4. The number of zeros of function y = x ^ 2-3x + 1
• 5. Find the zero point of function y = (3x ^ 2-x ^ 2) / (x ^ 2-1) + 1 / (1-x) - 2
• 6. The interval where the zeros of the function f (x) = 2x + 3x lie is______ ．
• 7. Try to find an interval of length one where the function y = (x-1) \ (3x + 2) has at least one zero point
• 8. The interval where the zeros of the function f (x) = - 1x + lgx are located is () A. （0，1）B. （1，2）C. （2，3）D. （3，10）
• 9. The interval where the zeros of the function f (x) = - (1 / x) + lgx lie is
• 10. The interval of zero point of function f (x) = lgx + X-5 is () A. （1，2）B. （2，3）C. （3，4）D. （4，5）
• 11. Given the function f (x) = TaNx, X belongs to (0, Wu / 2), if x1, X2 belong to (0, Wu / 2), X1 is not equal to X2, try to prove: 1 / 2 [f (x1) + F (x2)] > F [(x1 Given the function f (x) = TaNx, X belongs to (0, Wu / 2), if x1, X2 belong to (0, Wu / 2), X1 is not equal to X2, try to prove: 1 / 2 [f (x1) + F (x2)] > F [(X1 + x2) / 2]
• 12. Given the function f (x) = TaNx, X belongs to (0 ~ π / 2) and X1 = X2, compare the size of 1 / 2 (FX1 + FX2) and f (x1 + x2) / 2 Can we not use derivatives
• 13. Given the function f (x) = TaNx, X belongs to 0 to 90 degrees, if X1 and X2 belong to 0 to 90 degrees, and x1 ≠ X2, the proof is: 1 / 2 {f (x1) + F (x2)} > F {(x1 + x2) / 2}
• 14. Given the function f (x) = (KX + 1) / (x2 + C) (c > 0 and C is not equal to 1, K belongs to R), find the maximum value m and minimum value m of the function, and the value of K when M-M > = 1 Given the function f (x) = (KX + 1) / (x2 + C) (c > 0 and C is not equal to 1, K belongs to R), find the maximum m and minimum m of the function, and the value range of K when M-M > = 1
• 15. It is known that the function f (x) = KX + bx2 + C (C ＞ 0 and C ≠ 1, K ＞ 0) has a maximum point and a minimum point, and one of the extreme points is x = - C (1). Find another extreme point of function f (x). (2) let the maximum of function f (x) be m and the minimum be m. if M-M ≥ 1 is constant for B ∈ [1, 32], find the value range of K
• 16. Given the function f (x) = (KX + 1) / (x2 + C), find the maximum m and minimum m of the function, and the value range of M-M > = 1 Given the function f (x) = (KX + 1) / (x2 + C) (c > 0 and C is not equal to 1, K belongs to R), find the maximum m and minimum m of the function, and the value range of K when M-M > = 1 K radical 2 Thank you first
• 17. Given the function f (x) = x, G (x) = 3 / 8x ^ 2 + LNX + 2. (1) find the maximum and minimum points of the function f (x) = g (x) - 2F (x)
• 18. Given the function f (x) = - x ^ 2 + ax + 1-lnx, does the function have both maxima and minima? If so, find out the value range of A. if not, explain the reason
• 19. If the function f (x) = x ^ 3 + 2x ^ 2-ax + 3 has both minimum and maximum, then the value range of a is?
• 20. Let the square of function f (x) = x (x-a) have a maximum at x = 2, and find the value of real number a