Finding the zeros of the function y = (3x-x ^ 2) / (x ^ 2-1) + 1 / (1-x) - 2 | Math enthusiast | Mathematical art

Finding the zeros of the function y = (3x-x ^ 2) / (x ^ 2-1) + 1 / (1-x) - 2

The zero point of function y = (3x-x ^ 2) / (x ^ 2-1) + 1 / (1-x) - 2, that is, y = 0,
Let y = 0
(3x-x^2)/(x^2-1)+1/(1-x)-2=0
3x-x^2-x-1-2x^2+2=0
-3x^2+2x+1=0
3x^2-2x-1=0
(x-1)(3x+1)=0
X = 1, x = - 1 / 3, where x = 1, denominator = 0, so x = 1 is an increasing root,
So the zero point is: x = 1

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