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函數y=(3x-x^2)/(x^2-1)+1/(1-x)-2的零點,即y=0, 令y=0,得: (3x-x^2)/(x^2-1)+1/(1-x)-2=0 3x-x^2-x-1-2x^2+2=0 -3x^2+2x+1=0 3x^2-2x-1=0 (x-1)(3x+1)=0 x=1,x=-1/3,其中x=1時,分母=0,所以x=1是增根, 故零點為:x=1.
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