Given the function f (x) = (KX + 1) / (x2 + C), find the maximum m and minimum m of the function, and the value range of M-M > = 1 Given the function f (x) = (KX + 1) / (x2 + C) (c > 0 and C is not equal to 1, K belongs to R), find the maximum m and minimum m of the function, and the value range of K when M-M > = 1 K radical 2 Thank you first

Using discriminant method to find the range y = (KX + 1) / (x ^ 2 + C) YX ^ 2 + CY = KX + 1yx ^ 2-kx + CY-1 = 0. If the equation has a solution, then Δ = k ^ 2-4y (CY-1) ≥ 04cy ^ 2-4y-k ^ 2 ≤ 0 [1 - √ (1 + CK ^ 2)] / (2C) ≤ x ≤ [1 + √ (1 + CK ^ 2)] / (2C) maximum m = [1 + √ (1 + CK ^ 2)] / (2C) minimum M = [1 - √ (1 + CK ^ 2)] / (2

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1. It is known that the function f (x) = KX + bx2 + C (C ＞ 0 and C ≠ 1, K ＞ 0) has a maximum point and a minimum point, and one of the extreme points is x = - C (1). Find another extreme point of function f (x). (2) let the maximum of function f (x) be m and the minimum be m. if M-M ≥ 1 is constant for B ∈ [1, 32], find the value range of K
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