Given that the function f (x) = 1 / 3 x & # 179; + 1 / 2 ax & # 178; + BX has an extreme point in the interval [- 1,1), (1,3], then the value range of a-4b is

A: F (x) = (1 / 3) x & # 179; + (1 / 2) ax & # 178; + BX derivation: F & # 39; (x) = x & # 178; + ax + B has an extreme point in [- 1,1] and (1,3)] respectively, which indicates that the derivative function F & # 39; (x) has two zeros in the above two interval parabola F & # 39; (x) has an opening upward: F & # 39; (- 1) = 1-A + B & gt; = 0f & # 39

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