Let y = log2 ^ (0, + ∞). If f (x) = lgx, try to judge 1 / 2 "f (x1) + F (x2) and 1 / 2" f (x1) + F (x2) according to the image of F (x) F "((x1) + (x2)) / 2"

It is easy to know a (2,1), B (4,2), C (2, LG2), D (4,2lg2)
The slope of AB is 1 / 2 and the slope of CD is LG2 / 2
AB:y=x/2,
CD：y=xlg2/2.
The intersection coordinates of AB and CD are (0,0)

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