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Suppose that the cubic function f (x) = ax ^ 3 + BX ^ 2 + CX + D has a maximum 4 at x = 1 and a minimum 0 at x = 3, and the function image passes through the origin, the analytic expression of this function is obtained I don't think the answer is right. I want to find a positive solution. Don't copy it,
From the origin of F (x) image, f (0) = D = 0, f (x) = ax ^ 3 + BX ^ 2 + CX f '(x) = 3ax & # 178; + 2bx + C,
It is shown that f (x) has a maximum of 4 at x = 1 and a minimum of 0 at x = 3
f'(1)=3a+2b+c=0 f(1)=a+b+c=4
f'(3)=27a+6b+c=0 f(3)=27a+9b+c=0
unsolvable
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