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It is known that the function f (x) = 2asin (2x-3 parts) + B defined on [0,2 parts] has the maximum value of 1 and the minimum value of - 5. The values of a and B are obtained
If a ＞ 0, the maximum value is 2A + B = 1 and the minimum value is - radical 3A + B = - 5. The solution of x0d is a = 6 / (2 + radical 3) = 6 (2-radical 3) and x0db = 12 radical 3-11. If a ＜ 0, the maximum value is - radical 3A + B = 1 and the minimum value is 2A + B = - 5. The solution of x0d is a = - 6 (2-radical 3) and B = 7-12 radical 3
RELATED INFORMATIONS
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