Given the function f (x) = 2sinxcos (x + 30 degrees) - cos2x + m, find the minimum positive period of function f (x)

Given the function f (x) = 2sinxcos (x + 30 degrees) - cos2x + m, find the minimum positive period of function f (x)

F (x) = 2sinxcos (x + 30 degrees) - cos2x + M
=2sinx[(√3/2)cosx-(1/2)sinx]-cos2x+m
=√3sinxcosx-sin²x-cos2x+m
=(√3/2)sin2x-(1-cos2x)/2-cos2x+m
=(√3/2)sin2x-(1/2)cos2x+m-(1/2)
=sin(2x+π/6)+m-1/2
The minimum positive period is 2 π / 2 = π