If the complex Z satisfies f (1-z) = 2z-i, find the square root of (24-7i) f (1-I)

Let 1-z be equal to T. then 1-T is equal to Z. so f (T) is equal to 2 (1-T) - I. f (z) is equal to 2 (1-z) - I. This is just a transformation of the original function. Then substitute 1-I into f (z), f (1-I) is equal to 2-2 (1-I) - I. that is, equal to I. then I (24-7i), get 24i-7 (the square of I), the square of I is - 1, get 24i-7

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