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首先設1-z等於t.則1-t等於z.所以f(t)等於2(1-t)-i.f(z)等於2(1-z)-i.這只是轉化一下原函數.然後把1-i代入f(z),f(1-i)等於2-2(1-i)-i.即等於i.然後i(24-7i),得24i-7(i的平方),i的平方為-1,得24i-7….
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