In the complex range, the solution of the equation x ^ 2 + x-1-3i = 0 is?

Using the formula of root
obtain
X = [- 1 + radical (12I + 5)] / 2
=[- 1-radical (12I + 5)] / 2
Where root (12I + 5)
=Root (9 + 12I + 4I ^ 2)
=Root [(3 + 2I) ^ 2]
=3+2i
therefore
X = [- 1 + radical (12I + 5)] / 2 = I + 1
=[- 1-radical (12I + 5)] / 2 = - I-2

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