If complex x0 = 3 + 2I and Z * Z0 = 3Z + Z0, then complex Z=
z=a+bi
(a+bi)(3+2i)=3(a+bi)+3+2i
(3a-2b)+(2a+3b)i=(3a+3)+(3b+2)i
therefore
3a-2b=3a+3
2a+3b=3b+2
b=-3/2,a=1
So z = 1-3i / 2
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