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照樣用求根公式 得到 x=[-1+根號(12i+5)]/2 =[-1-根號(12i+5)]/2 其中根號(12i+5) =根號(9+12i+4i^2) =根號[(3+2i)^2] =3+2i 所以 x=[-1+根號(12i+5)]/2=i+1 =[-1-根號(12i+5)]/2=-i-2
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