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設z=a+bi 則(3+2i)(a+bi)=3(a+bi)+3+2i 即(3a-2b)+(2a+3b)i=(3a+3)+(3b+2)i 所以3a-2b=3a+3,2a+3b=3b+2 故a=1,b=-3/2 所以z=1-3i/2
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