When k______ The equation x 2 + (2k + 1) x-k 2 + k = 0 has real roots

∵ the equation x2 + (2k + 1) x-k2 + k = 0 has real roots, namely △≥ 0, that is △ = (2k + 1) 2-4 (- K2 + k) = 8k2 + 1, ∵ 8k2 ≥ 0, that is, K takes any real number, the original equation has real roots. So the answer is to take any real number

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