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It is known that the product of a linear binomial and x ^ 2-3x + 1 does not contain a quadratic term. Please write a linear binomial satisfying the condition
Let this binomial be: ax + B, then (AX + b) (X & # 178; - 3x + 1) = ax & # 179; - 3ax & # 178; + ax + BX & # 178; - 3bx + B = ax & # 179; + (B-3A) x & # 178; + (a-3b) x + B, because there is no quadratic term, so a-3b = 0, that is, a = 3b, let a = 1, B = 3, then the binomial is: x + 3, let x = 2, B = 6
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