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設這個一次二項式為:ax+b則(ax+b)(x²-3x+1)=ax³-3ax²+ax+bx²-3bx+b=ax³+(b-3a)x²+(a-3b)x+b因為不含二次項,所以a-3b=0,即a=3b令a=1,b=3,可得該一次二項式為:x+3令x=2,b=6,可得該一...
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