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根據複數的性質:z1/z2=z1/z2 (根號2 -2ai)/(a+2i)=(根號2 -2ai)/(a+2i) =根號(2+4a^2)/根號(a^2+4) =根號2 所以:(2+4a^2)/(a^2+4)=2 解得:a=正負根號3
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