設z=a+bi,且a,b滿足a(1+i)³;+(2-5i)=bi-4,則z的共軛複數=

設z=a+bi,且a,b滿足a(1+i)³;+(2-5i)=bi-4,則z的共軛複數=

(1+i)²;=1+2i-1=2i
所以2ai(1+i)+2-5i=bi-4
(-2a+2)+(2a-5)i=bi-4
所以-2a+2=-4
2a-5=b
a=3,b=1
所以z的共軛=a-bi=3-i