Let z = a + bi, and a, B satisfy a (1 + I) &# 179; + (2-5i) = bi-4, then the conjugate complex number of Z is=

(1+i)²=1+2i-1=2i
So 2ai (1 + I) + 2-5i = bi-4
(-2a+2)+(2a-5)i=bi-4
So - 2A + 2 = - 4
2a-5=b
a=3,b=1
So the conjugate of Z = a-bi = 3-i

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