The module of complex number Z = [(1 + I) ^ 200 * (6 + 2I) - (1-I) ^ 198 * (3-I)] / [(1 + I) ^ 198 * (23-7i) + (1-I) ^ 194 * (10 + 2I), find | Z| Don't use triangles. I haven't taught you

The module of complex number Z = [(1 + I) ^ 200 * (6 + 2I) - (1-I) ^ 198 * (3-I)] / [(1 + I) ^ 198 * (23-7i) + (1-I) ^ 194 * (10 + 2I), find | Z| Don't use triangles. I haven't taught you

（1+i)^200=(1+2i+i^2)^100=(2i)^100=2^1002^100*(6+2i)=3*2^101+2^101i(1-i)^198=(1-2i-1)^99=2^99i2^99i*(3-i)=3*2^99i+2^99(1+i)^198*(23-7i)+(1-i)^194*(10+2i)=-2^99i*(23-7i)+2^97i*（10+2i)=z=(26+14i)/(-41i...

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