Find the minimum value of 3x ^ 2 + 6x + 5 / 0.5x ^ 2 + X + 1

Find the minimum value of 3x ^ 2 + 6x + 5 / 0.5x ^ 2 + X + 1

3x ^ 2 + 6x + 5 / 0.5x ^ 2 + X + 1 = (6x ^ 2 + 12x + 10) / (x ^ 2 + 2x + 2) = (6x ^ 2 + 12x + 12-2) / (x ^ 2 + 2x + 2) = 6-2 / ((x + 1) ^ 2 + 1) because (x + 1) ^ 2 + 1) ≥ 1, the minimum value of 6-2 / ((x + 1) ^ 2 + 1) is 4. Therefore, the minimum value of 3x ^ 2 + 6x + 5 / 0.5x ^ 2 + X + 1 is 4