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3x^2+6x+5/0.5x^2+x+1=(6x^2+12x+10)/(x^2+2x+2)=(6x^2+12x+12-2)/(x^2+2x+2)=6-2/((x+1)^2+1)因(x+1)^2+1)≥1所以6-2/((x+1)^2+1)的最小值是4.囙此3x^2+6x+5/0.5x^2+x+1的最小值是4
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