The derivative of y = e ^ TaNx TaNx is to the power of E and 2 is to the power of TaNx

The derivative of y = e ^ TaNx TaNx is to the power of E and 2 is to the power of TaNx

Solutions: y = e ^ (TaNx) &# 178; y '= e ^ (TaNx) &# 178; * (TaNx) &# 178;' = e ^ (TaNx) &# 178; * 2tanx (TaNx) '= e ^ (TaNx) &# 178; * 2tanx (secx) &# 178; = 2tanx (secx) &# 178; e ^ (TaNx) &# 178; = 2sinx (secx) &# 179; e ^ (TaNx) &#