The derivative of y = e ^ TaNx TaNx is to the power of E and 2 is to the power of TaNx
Solutions: y = e ^ (TaNx) 178; y '= e ^ (TaNx) 178; * (TaNx) 178;' = e ^ (TaNx) 178; * 2tanx (TaNx) '= e ^ (TaNx) 178; * 2tanx (secx) 178; = 2tanx (secx) 178; e ^ (TaNx) 178; = 2sinx (secx) 179; e ^ (TaNx)