Let f (x) = xsinx (x ∈ R). If x ∈ (- π / 2,3 π / 2) and f (x) ≥ (- 1 / 2) x, the value range of X is obtained

Let f (x) = xsinx (x ∈ R). If x ∈ (- π / 2,3 π / 2) and f (x) ≥ (- 1 / 2) x, the value range of X is obtained

When x is greater than or equal to 0, it can be simplified as SiNx ≥ - 1 / 2
x∈(π,7π/6),
When x