If f (SiNx) = 3-cos2x, then f (cos15 degrees)=
cos15°=sin(90°-15°)=sin75°
So f (COS 15 °)
=f(sin75°)
=3-cos(2×75°)
=3-cos150°
=3-(-√3/2)
=3+√3/2
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