Let a = (2, - 3), B = (- 4,0), C = (- 5,6), find - 2A + 3b-4c
solution
a=(2,-3)
b=(-4,0)
c=(-5,6)
-2a+3b-4c
=(-2×2+3×(-4)-4×(-5),-2×(-3)+3×0-4×6)
=(4,-18)
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