Let a = (2, - 3), B = (- 4,0), C = (- 5,6), find - 2A + 3b-4c

Let a = (2, - 3), B = (- 4,0), C = (- 5,6), find - 2A + 3b-4c

solution
a=(2,-3)
b=(-4,0)
c=(-5,6)
-2a+3b-4c
=(-2×2+3×(-4)-4×(-5),-2×(-3)+3×0-4×6)
=(4,-18)